Molar solubility
Calculate the molar solubility of Cr(OH)3 in 0.54 M NaOH. Kf for Cr(OH)4 is 8x10^29 please help with this problem!
I've tried many ways and I only have one try left to get it right. my first though was to look up the ksp for Cr(OH)3 which was 6.7x10^31 I then multiplied it by the Kf to get the new K and set up an equation as
.536=x^2/.54x
I got .33 and it told me it was wrong but then I realized it only asked for 1 sig fig so maybe thats why it didn't accept it. or I'm just doing the whole thing wrong.
