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Old Apr 24th 2017, 02:28 AM   #1
Kaber
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The combustion of pentane produces heat according to the equation

C5H12(l) + 8O2(g) = 5CO2(g) + 6H2O(l)

deltaHrxn = -3510kJ/mol

How many grams of C5H12 are needed per 2.50*10^3kJ of heat released?


My attempt:

2.50*10^3kJ 1 mol C5H12 72.146g
x ___________ x ___________ = 51.4g
3510kJ 1 mol C5H12


Am I correct? If not, please help. Thank you.

Last edited by Kaber; Apr 24th 2017 at 02:37 AM.
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Old Apr 25th 2017, 05:14 AM   #2
MatthijsM
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Looks correct to me.
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Old Apr 25th 2017, 09:05 AM   #3
Kaber
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Ty sir
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