Chemistry Help Forum Molarity

 Dec 3rd 2017, 02:25 PM #1 shilparao Junior Member   Join Date: Nov 2017 Location: US Posts: 3 Molarity Can anyone help me with this question? What is the molarity of each ion present in aqueous solutions prepared by dissolving 15.0 g of the following compounds in water to make 655 mL of solution? a.) scandium(iii) iodide b.) sodium carbonate c.) magnesium phosphate d.) potassium oxide I think my main issue is writing the reactions themselves, as well as the fact that I don't completely grasp the concept of ions in relation to calculating molarity. for a) ScI3 --> Sc^3+ + 3I^1- Is that correct? If so, my next steps would be to: 1. calculate MM of ScI3 = 425.66 2. Find molarity: 15g ScI3 = 0.035 mol [ScI3] = 0.035 mol/0.655 L = 0.0534 mol/L Using this, I know that: - the molarity of Sc is 0.0534 - the molarity of I is 0.0534*3 = 0.1602 That's as far as i've gotten - I still feel like I might be doing something wrong. Last edited by shilparao; Dec 3rd 2017 at 02:43 PM. Reason: I forgot to put in my attempt
 Dec 4th 2017, 11:22 AM #2 ChemTeam Junior Member   Join Date: Feb 2015 Posts: 4 Every step of your calculation is completely correct.

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