 Chemistry Help Forum can anyone please help Jan 3rd 2019, 06:36 AM #1 nathanwxm Junior Member   Join Date: Jan 2019 Location: wales Posts: 2 can anyone please help A reaction mixture contains 5.00 g of AgNO3 and 25.0 g of CaCl2 dissolved in water. (a) Write a balanced chemical equation for the reaction. (b) Calculate the number of grams of AgCl that can be formed after determining the limited reagent.   Feb 3rd 2019, 05:12 PM #2 DrPelezo Junior Member   Join Date: May 2015 Location: Houston, TX Posts: 24 2AgNO₃(aq) + CaCl₂(aq) => Ca(NO₃)₂(aq) + 2AgCl(s) 5.00-g AgNO₃ = (5.00-g/169-g/mole) = 0.030-mole AgNO₃ 25.00-g CaCl₂ = (25.00-g/110-g/mole) = 0.227-mole CaCl₂ Divide moles by respective coefficients => smaller value is limiting reactant. AgNO₃ => 0.030/2 = 0.015 => Limiting reactant CaCl₂ => 0.227/1 = 0.227 Since coefficient of AgNO₃ and AgCl are the same, the amount of AgCl produced is 0.030-mole 0.030-mole AgCl = 0.030-mole x 142-g/mole = 4.26-g AgCl (Theoretical)  Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode 