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Old Dec 7th 2011, 10:07 AM   #1
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Acids and Bases

in my notes, it reads that the:
"dilution of vinegar results in lower acidity and higher percent ionization".

is the acidity lower because concentration is decreased? and is % ionization higher because water ionizes more than a weak acid does?

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Old Dec 7th 2011, 10:56 PM   #2
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Vinegar is ethanoic acid: CH3COOH, it dissociates like this:

CH3COOH <===> CH3COO^- + H^+

Adding more water means that the volume of the solution increases while the amount of moles of the acid remains constant. Therefore, the concentration of H^+ ions decrease.

But as per Le Chatelier's Principle, the equilibrium initially set up will shift to the right and more H^+ will be formed, though there cannot be as much H^+ formed as to get back the previous concentration of H^+.
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