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Old Mar 13th 2018, 01:18 PM   #1
Robertgc3
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Determine Enthalpy Change

Please help me answer and understand this:

Chloroform, CHCl3, is formed by the following reaction:

CH4(g) + 3 Cl2(g) → 3 HCl(g) + CHCl3 (g)

Determine the enthalpy change for this reaction (ΔHrxn), using the following:

enthalpy of formation of CHCl3 (g), ΔHf = 103.1 kJ/mol

CH4(g) + 2 O2(g) → 2 H2O(l) + CO2(g) ΔHrxn = 890.4 kJ/mol

2 HCl (g) → H2 (g) + Cl2(g) ΔHrxn = + 184.6 kJ/mol

C (graphite) + O2(g) → CO2(g) ΔHrxn = 393.5 kJ/mol

H2 (g) + O2(g) → H2O(l) ΔHrxn = 285.8 kJ/mol



+ 145.4 kJ

305.3 kJ

145.4 kJ

+ 305.3 kJ

103.1 kJ
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