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Old Jan 3rd 2019, 07:36 AM   #1
nathanwxm
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can anyone please help

A reaction mixture contains 5.00 g of AgNO3 and 25.0 g of CaCl2 dissolved in water. (a) Write a balanced chemical equation for the reaction. (b) Calculate the number of grams of AgCl that can be formed after determining the limited reagent.
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Old Feb 3rd 2019, 06:12 PM   #2
DrPelezo
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2AgNO₃(aq) + CaCl₂(aq) => Ca(NO₃)₂(aq) + 2AgCl(s)
5.00-g AgNO₃ = (5.00-g/169-g/mole) = 0.030-mole AgNO₃
25.00-g CaCl₂ = (25.00-g/110-g/mole) = 0.227-mole CaCl₂
Divide moles by respective coefficients => smaller value is limiting reactant.
AgNO₃ => 0.030/2 = 0.015 => Limiting reactant
CaCl₂ => 0.227/1 = 0.227
Since coefficient of AgNO₃ and AgCl are the same, the amount of AgCl produced is 0.030-mole
0.030-mole AgCl = 0.030-mole x 142-g/mole = 4.26-g AgCl (Theoretical)
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