If 75.0mL of a 0.0010M aqueous solution of Fe(NO3)2 was added to 100.0mL of a 0.00050M aqueous solution of NaOH would a precipitate form?
How would I do this?
I thought I would first draw out the molecular and net ionic equations:
Fe(NO3)2 + 2NaOH --> Fe(OH)2 + 2NaNO3
Fe2+ (aq) + 2OH- (aq)...