I have a trial function:
phi(x)= (2b/pi)^1/4 *e^-bx^2
and a potential V(x)= a* |x|; |x|=x when x>0 and |x|=-x when x<0.
I am supposed to determine the groundstate energy.
I know what does variation principle mean. But my problem is that, i don't know how to solve the integral.