Yes that's good.

Since the question gives the available mass of lithium to 2 decimal places (dp) you should work to 2 dp.

Do you understand this (it is an important side issue) ?

Whoopsy - I just noticed you are asked to calculate for 1.75 moles of lithium, not 1.75 grams so lets do that instead.

So your correct equation says (in words)

6 times 6.94 grams of Li makes 2 times 34.83 grams of hydride.

That is

6 x 6.94 grams makes 2 x 34.83 grams

That is

6 gram-moles makes 69.66 g

That is

1 gram-mole makes \(\displaystyle \frac{{69.66}}{6}\) g

1.75 gram-moles makes 1.75 x \(\displaystyle \frac{{69.66}}{6}\) g