"To prepare your solutions, you will need to weight out quinine sulfate and dilute it in an aqueous solution of .05M H2SO4. Calculate the volume of H2SO4 (12mol/L) that you will need to prepare 250mL of a .05mol/L H2SO4 solution. We recommend that you prepare 50mL of a quinine stock solution that is 25 times more concentrated than your lowest solution concentration. Given the formula weight for quinine sulfate is 782.96g/mol calculate how many grams of quinine sulfate you will need. Calculate the volume of the stock solution you will put into these flasks."

The stock solution that I want to make that would be 25 more concentrated than the lowest concentration is .005moles/L

To prepare the 250mL of .05mol/L H2SO4 I did the following calculation:

(12mol/L)*x=(.05mol/L)*(250ml)

x= 1.04166mL of (12mol/L) H2SO4 to make (.05mol/L) H2SO4

My question is what do I add to the 1.04166mL of 12mol/L H2SO4 to dilute the solution to 250ml? So if I am using 1.04166mL of the 12mol/L H2SO4 what is the rest of the 249mL for the dilution?

My second question is if I want my stock solution of quinine sulfate to be .005mole/L does this mean that I will use (.005mol/L)*782.96(g/mol)= 3.9148grams of quinine sulfate to make this solution, as well as (.005mol/L)*(50mL)=(.05mol/L)*x where x is 5mL of .05mol/L H2SO4.

Therefore I would put 3.9148grams of quinine sulfate and then add 5ml of the .05mol/L H2SO4 and then dilute it with something to make 50ml of .005mol/L solution?

Again what do I use for the other 45mL of solution that isnt the 5ml of .05mol/L H2SO4

Any help or thoughts are greatly appreciated! Thank you